Program to find the number if it is within 100 of 1000 or 2000

Solution

def near_thousand(n):
    return (abs(1000 - n) <= 100) or (abs(2000 - n) <= 100)
print(near_thousand(1000))
print(near_thousand(900))
print(near_thousand(800))
print(near_thousand(2200))